Question

if an electron is revolving in its bohr orbit having bohr radius of `0.529Å`, then the radius of third orbit is
A. `4234Å`
B. `4496Å`
C. `4.761Å`
D. `5125nm`

Answer 1

Correct Answer - C
As`r_n=n^2a_0`,
Here, `a_0=0.529Å` and `n=3`
`therefore r_(n=3)=(3)^2a_0=9xx0.529Å=4.761Å`