We know that, equation of parabola having vertex at origin and axis along positive y-axis is x2 = 4ay, where a is the parameter........(i)
On differentiating Eq. (i) w.r.t. 'x' , we get
On substituting the value of 4a from Eq. (ii) to Eq. (i), we get
or xy' - 2y = 0, which is the required differential equation