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in Chemistry by (81.1k points)
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The cell , `Zn | Zn^(2+) (1M) || Cu^(2+) (1M) Cu (E_("cell")^@ = 1. 10 V)`,
Was allowed to be completely discharfed at `298 K `. The relative concentration of `2+` to `Cu^(2+) [(Zn^(2=))/(Cu^(2+))]` is :
A. `9.65 xx 10^(4)`
B. antilog (24.08)
C. `37.3`
D. `10^(37.3)`

1 Answer

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by (80.8k points)
 
Best answer
Correct Answer - D
`E = E^(@) - (0.059)/(2) log.([Zn^(2+)])/([Cu^(2+)])`
`0 = 1.10 - (0.059)/(2) log. ([Zn^(2+)])/([Cu^(2+)])`
`log .([Zn^(2+)])/([Cu^(2+)]) = 37.3 :. ([Zn^(2+)])/([Cu^(2+)]) = 10^(37.3)`

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