Let the rate equation be `k[A]^(x)[X]^(y)`
From `"From expt"(1),0.3xx10^(-4)=[0.03]^(x)[0.03]^(y)" "....(i)`
`"From expt"(2),1.2xx10^(-4)=[0.06]^(x)[0.06]^(y)" "....(ii)`
`(1.2xx10^(-4))/(0.3xx10^(-4))=([0.06]^(x)[0.06]^(y))/([0.03]^(x)[0.03]^(y))`
`" " =2^(x)xx3^(x)=4 " "....(iii)`
Similarly, from expt. (1) and expt (3)
`" " 2^(x)xx3^(y)=9 " " ....(iv)`
Solving eqs. (ii) and (iv),
`" " x=0,y=2`
Rate equation `" "` Rate =`k[B]^(2)`
Consider eq. (i) again,
`k=(0.3xx10^(-4))/([0.03]^(2))=3.33xx10^(-2)"mol"^(-1)L s^(-1)`