Correct Answer - 6
For reflection by concave mirror.
`(1)/(-F)=(1)/(v)+(1)/(-4F//3)`
`rArr v=-4F` Hence `m_(1)=(-v)/(u)=-3`
For reflection by concave mirror,
`u=F , f=+2F (1)/(2F)=(1)/(v)+(1)/(F) (1)/(v)=(1)/(2F)-(1)/(F)=-(1)/(2F) v=-2F`
magnification by concave mirror.
`m_(2)=-(-(2F)/(F))=2`
Net magnification `=m_(1)m_(2)=(-3)(2)=-6`
