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An alcohol gives Lucas test within 5 minutes. The structure of alcohool , 0.22 of which liberates 56 mL of `CH_(4)` at STP on treatment with `CH_(3)MgI` will be `:`
A. `CH_(3)-underset(OH)underset(|)(C)H-CH_(3)`
B. `CH_(3)CH_(2)-underset(OH)underset(|)(C)H-CH_(3)`
C. `(CH_(3))_(2)CH-underset(OH)underset(|)(C)H-CH_(3)`
D. `(CH_(3))_(3)C-underset(OH)underset(|)(C)H-CH_(3)`

1 Answer

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by (80.8k points)
 
Best answer
Correct Answer - C
[Hint]
All the given alcohols `(2^(@))` give Lucas test within 5 minutes.
Let the molecular mass of alcohol is M.
`(56)/(22400)=(0.22)/(M)` or `M=(22400xx0.22)/(56)=88`
Now, general formula of alcohol is `C_(n)H_(2n+1)` OH which corresponds to molecular mass 88 ony when value of `n=5`. Thus `2^(@)` alcohol having five carbon atoms will be (c ) only.

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