Question

Calculate degree of hydrolysis(h) and pH of solution obtained by dissolving `0.1` moles of `CH_(3)COOHNa` in water to get `100L` of solution .Take `K_(a)` of acetic acid `=2xx10^(-5)` at `25^(@)C`.

Answer 1

`c=(0.1)/(100)=1xx10^(-3)M`
`K_(h)=(K_W)/(K_(a))=(10^(-14))/(2xx10^(-5))=5xx10^(-10)rArr h=sqrt((K_(h))/(c))=sqrt((5xx10^(-10))/(2xx10^(-5)))=5xx10^(-3)=0.5%`
`,.pH=(1)/(2)[pK_(w)+pK_(a)+logc]=(1)/(2)[14+5-log2+log10^(-3)]=(1)/(2)[15.7]=7.85`