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If for a sample of size 60, we have the following information `sumxi2=18000a n dsumxi=960` , then the variance is 6.63 (b) 16 (c) 22 (d) 44
A. 6.63
B. 16
C. 22
D. 44

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Correct Answer - D
Variance `=(sum x_(i)^(2))/(n)-((sum x_(i))/(n))^(2)`
`=(18000)/(60)-((960)/(60))^(2)=300-256=44`

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