Question

(i)`P+C("carbon")+Cl_(2)toQ+CO uarr` , (ii)`Q+H_(2)OtoR+HCl`
(iii)`BN+H_(2)O to R+NH_(3)` , (iv)`Q+LiAIH_(4) to S+LiCl+ AlCl_(3)`
(v)`S+H_(2)toR+H_(2) uarr` , (vi)`S+NaH to T`
(`P,Q,R,S` and `T` do not represent their chemical symbols)
Compound S is: (I) an odd compound (II) (III) an electron deficient compound (IV) a hybridized compound Choose the correct code:
A. III
B. I,III
C. II,III,IV
D. I,II,IV

Answer 1

Correct Answer - A
(i)`B_(2)O_(3)(P)+3C+3Cl_(2) to 2BCl_(3) (Q) +3CO uarr`
(ii)`BCl_(3)(Q)+3H_(2)O to H_(3)BO_(3)(R)+3HCl`
(iii)`BN+3H_(2)O to H_(3)BO_(3)(R ) + NH_(3)`
(iv)`4BCl_(3)(Q)+3LiAlH_(4) to 2B_(2)H_(6)(S)+3LiCl+3AlCl_(3)`
(v)`B_(2)H_(6)+6H_(2)O to 2H_(3)BO_(3) (R)+6H_(2) uarr`
(vi)`B_(2)H_(6)(S)+2NaH to 2NaBH_(4)(T)`