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The number of real values of the parameter `k` for which `(log_(16)x)^2-(log)_(16)x+(log)_(16)k=0` with real coefficients will have exactly one solution is 2 (b) 1 (c) 4 (d) none of these
A. 2
B. 1
C. 4
D. none of these

1 Answer

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Best answer
Correct Answer - A
` log_(16) x = (1 pm sqrt(1-4 log _(16) k))/2`
For exactly one solution, ` 4 log_(16) k = 1`.
` rArr k^(4) = 16, i.e., k=2, -2`.

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