Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
107 views
in Chemistry by (84.4k points)
closed by
Statement-1 :`Cu^(2+)` and `Cd^(2+)` ions form complexes with excess of potassium cyanide solution.
Statement-2 : On passing `H_(2)S` gas, complex `[Cu(CN)_(4)]^(3-)` is not effected but `[Cd(CN)_(4)]^(2-)` gives yellow precipitated.
A. STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is correct explanation for STATEMENT-1
B. STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is not correct explanation for STATEMENT-2
C. STATEMENT-1 is true, STATEMENT-2 is false
D. STATEMENT-1 is false, STATEMENT-2 is true

1 Answer

0 votes
by (82.0k points)
selected by
 
Best answer
Correct Answer - B
Statement-1 :`Cu^(2+) +6CN^(-) to [Cu(CN)_(4)]^(3-) + (CN)_(2) , Cd^(2+) + 4CN^(-) to [Cd(CN)_(4)]^(2-)`
Statement-2 :`[Cu(CN)_(4)]^(3-)` being stable complex is not effected by `H_(2)S` gas but `[Cd(CN)_(4)]^(2-)` is not so stable and gives yellow precipitate with `H_(2)S`.
`[Cd(CN)_(4)]^(2-)+H_(2)S to CdS darr ("yellow")+2H^(+) + 4CN^(-)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...