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A body is projected up such that its position vector varies with time as `vecr={3thati+(4t-5t^(2))hatj} m`. Here `t` is in second.The time when its `y`-coordinate is zero is

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y co-ordinate of particle `=4t-5t^(2)=0rArrt=(4)/(5)s=40.8s`
At that time `x=3xx(4)/(6)=(12)/(5)m=2.4m`

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