Question

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is
A. `theta=tan^(-1)(2)`
B. `theta=45^(@)`
C. `theta=tan^(-1)((1)/(4))`
D. `theta=tan^(-1)(4)`

Answer 1

Correct Answer - D
`R=H_("max")rArr(2u^(2)sin theta cos theta)/(g)=(u^(2)sin^(2)theta)/(2g)`
`rArr tan theta=4 rArr theta=tan^(-1)(4)`