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If voltage across a bulb rated 220 volt-100 watt drops by `2.5 %` of its value, the percentage of the rated value by which the power would decrease is
A. 0.05
B. 0.1
C. 0.2
D. 0.025

1 Answer

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Best answer
`P prop V^(2)` So `(Deltap)/(P)=2(DeltaV)/(V)=5%`

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