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A large open tank has two holes in the wall. One is a square hole of side L at a depth y from the top and the other is a circular hole of radius R at a depth 4y from the top. When the tank is completely filled with water, the quantities of water flowing out per second from both holes are the same. Then, R is equal to
A. `(L)/sqrt(2pi)`
B. `2 pi L`
C. `L`
D. `(L)/(2pi)`

1 Answer

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Best answer
Correct Answer - A
Volume flowing per sec `V=av`
`L^(2)sqrt(2gy)=pir^(2)sqrt(2g(4y))" "impliesL^(2)=2piR^(2)`
`R=(L)/sqrt(2pi)`

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