`.^(23)` Na is the more stable isotope of Na. Find out the process by which `._(11)^(24)` Na can undergo radioactive decay.

`n//p` ratio of `^(24)Na` is `13//11` and thus greater than one. It will therefore decay following `beta`-emission.
`_(11)^(24)Na rarr `_(12)^(24)Mg+ `_(-1)^(0)e```

`.^(23)` Na is the more stable isotope of Na. Find out the process by which `._(11)^(24)` Na can undergo radioactive decay.

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