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Consider the reaction

4NO2 (g) + O2 (g)→  2N2 O5 (g),  ΔrH = 111kJ

if N2O5(s) is formed instead of N2O5(g) in the aboe reaction the ΔrH value will be :–

(Given ΔH of sublimaton for N2O5 is 54 kJ mol–1)

(a) – 165 kJ 

(b) +54 kJ

(c) +219 kJ 

(d) –219 kJ

1 Answer

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Best answer

Correct option (d) –219 kJ

Explanation:

Note, ΔH of sublimation of N2O5 (s) is + 54 kJ mol–1.

Thus, for reverse process, it is –54 kJ mol–1.

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