Question

The EMF of the standard weston cadmium cell
`Cd(12.5%)` in `Hg|3CdSO_(4),8H_(2)O` (solid) | satd. Soln of `CdSO_(4)||Hg_(2)SO_(4)(s)|Hg` is
`1.0180` volts at `25^(@)C` and the temperature coefficient of the cell, `((delE)/(delT))_(P)=-4.0xx10^(-5)//"degree"`, calculate `triangleG` `triangleH` and `triangleS` for the reactionn in the cell when `n=2`

Answer 1

Correct Answer - `triangleG=-196.5kJ:triangleH=198.8kJ;triangleS=-7.72Jd_(eg-1)`
`Cd(12.5%)` in `Hg//3CdSO_(4),8H_(2)("solid")//"satd sol of " CdSO_(4)||Hg_(2)SO_(4(s))\Hg,E=1.018"volt"`
`((dE)/(dT))_(P)=-nEF=-21.018xx96500=-196.474kJ`
`triangleS=nF.((dE)/(dT))_(P)=2xx96500xx(-4xx10^(-5))=7.72JK^(-1)`
`triangleG=triangleH-TtriangleS`
`triangleH=-196.474+(298xx(-7.72))/(1000)=-196.474-2.3=198.774kJ`