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Gold number of haemoglobin is `0.03`. Hence, `100 mL` of gold sol will require haemoglobin so that gold is not coagulated by `1 mL` of `10%` NaCl solution:
A. `0.03 mg`
B. `30 mg`
C. `0.30 mg`
D. `3 mg`

1 Answer

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Best answer
Correct Answer - C
`0.03`= weight to Hb in mg xx `10//100`
weight of Hb in mg `=0.30`

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