Correct Answer - B
`(0.020)u=(1)V+3V`
`V=((0.02u)/(4))=(5xx10^(-3))u`
`(0.020)u=1V+(0.020)u_(1)`
`(0.020)u=(5xx10^(-3))u+(0.020)u_(1)`
`(2xx10^(-2))u=(0.5xx10^(-2))u+(2xx10^(-2))u_(1)`
`1.5 u \2u_(1)`
`u_(1)=((1.5)/(2)u)=(3)/(4)u`
`(Deltau)/(u)xx100=25%`