Correct Answer - {4,5,6,7,8,9,10 } (b ) { 1,3,5,7,9,} (c ) {1,2,3,4,5,6,8,}
Given,X= {1, 2, 3, ...,10}
(a) Since `1^2,2^2,3^2 in X`
`{a|a in X and a^2 notin X}` ={4,5,6,7,8,9,10}
(b) ` a in X but a//2 of 24`
`rArr a=1,3,5,7,9`
`therefore of 24`
`rArr {a|a in X but a//2 in X} `= {1,3,5,7,9}
( c) a is factor of 24
`rArr a= 1,2,3,4,5,6,8 `
`therefore { a|a is " factor of " 24 }={ 1,2,3,4,6,5,6,8}`