Correct Answer - A
The ration of the ships A, B and C for arriving safely are `2:5,3:7,and 6:11,` respectively. Therefore is `2//(2+5)=2//7.`
Similarly, for B the probability is `3//(3+7)=3//10` and for C the probability is `C=6//(6+11)=6//17.`
Therefore the probability of all the ships for arriving seafly is `(2//7)xx(3//10)xx(6//17)=18//895.`
Therefore, the probability of all the ships for arriving safely is
`(2//7)xx(3//10)xx(6//17)=18//595.`