Question

Find values of k if area of triangle is 4 square units and vertices are

(i) (k, 0), (4, 0), (0, 2)            (ii) (−2, 0), (0, 4), (0, k)

Answer 1

We know that the area of a triangle whose vertices are (x₁, y₁), (x_2, y₂), and (x₃, y₃) is the absolute value of the determinant (Δ), where

It is given that the area of triangle is 4 square units.

(i) The area of the triangle with vertices (k, 0), (4, 0 (0, 2) is given by the relation,

(ii) The area of the triangle with vertices (−2, 0), (0, 4), (0, k) is given by the relation,