Boron always forms covalent compound.
The small size of `B^(3+)` favours formation of covalent compound.
A. Statement I is correct, Statement II is correct Statement II is the correct explanation of Statement I
B. Statement I is correct, Statement II is correct Statement II is no the correct explanation of Statement I
C. Statement I is correct, Statement II is incorrect
D. Statement I is incorrect, Statement II is correct
