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JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
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CLASS 8 FOUNDATION COURSE
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`y=(x+sin x)/(x+cos x)`

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Correct Answer - `(cos x - sinx + x(cos x + sin x)+1)/((x+ cos x)^(2))`
Using quotient rule, we have
`(dy)/(dx)=(d)/(dx)((x+ sin x)/(x+ cos x))`
`=((x+ cos x).(d)/(dx)(x+ sin x)-(x + sin x).(d)/(dx)(x+ cos x))/((x+ cos x)^(2))`
`=((x+cos x)cdot(1 + cos x)-( x+ sin x)cdot(1-sin x))/((x+cos x)^(2))`
`=(x+cos x + x cos x +cos^(2)x-x- sin x + x sin x + sin^(2)x)/((x+ cos x )^(2))`
`=(cos x - sin x + x cos x + x sin x + cos^(2) x + sin ^(2) x)/((x+ cos x)^(2))`
`=(cos x - sin x + x (cos x + sin x)+1)/((x+ cos x)^(2))`

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