Given `MPC = 2 MPS`
Add MPS on both sides
`MPC + MPS = 2 MPS + MPS`
Since `MPC + MPS = 1`, Substituting
`3 MPS = 1`
`MPS = (1)/(3)`
`:. MPC = 1 - (1)/(3) = (2)/(3)`
Multiplier `= (1)/(MPS) " or " (1)/(1-MPC)`
`= (1)/((1)/(3)) " or " (1)/(1-(2)/(3)) = 3`