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`inte^(tanx)(sinx-secx)dx` is equal to

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`inte^(tanx)(sinx-secx)dx` is equal to
A. `e^(tanx)cosx +C`
B. `e^(tanx)sinx +C`
C. `-e^(tanx)cosx +C`
D. `e^(tanx)sec x +C`
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1 Answer

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Best answer
Correct Answer - C
`I=inte^(tanx)(sinx-secx)dx`
`=int sinx e^(tanx)dx-int secx e^(tanx)dx`
`=-e^(tanx)cosx+int cos x e^(tanx)sec^(2)x dx-int sec x e^(tanx) dx`
`= -cosx e^(tanx) +C`
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