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In the figure, AB = 5 cm, ∠CAB = 90º ∠CBA = 60º, AP is the bisector is ∠CAB

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In the figure, AB = 5 cm, ∠CAB = 90º ∠CBA = 60º, AP is the bisector is ∠CAB

(a) What is the length of BC ?

(b) What is CP : PB ?

(c) Find the length of PB.

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1 Answer

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(a) In DABC, AB = 5 cm

ÐBAC = 90º, ÐCBA = 60º

(b) In ΔABC, AP is the angle bisector of ∠BAC

PB = 5 x 0.732 = 3.660 cm

PB = 3.66 cm = 3.7 cm

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