If `K_(1) and K_(2)` are maximum kinetic energies of photoelectrons emitted when light of wavelength `lambda_(1) and lambda_(2)` respectively are incident on a metallic surface. If
`lambda_(1)=3lambda_(2)` then
A. `2K_(1)=K_(2)`
B. `K_(1)=2K_(2)`
C. `K_(1)lt(K_(2))/(2)`
D. `K_(1)lt2K_(2)`