Question

A particle executes simple harmonic motion about the point x = 0. At time t = 0 it has displacement x = 2 cm and zero velocity . If the frequency of motion is 0.25 s^-1, find 

(a) the period 

(b) angular frequency 

(c) the amplitude 

(d) maximum speed 

(e) the displacement at t = 3 s and

(f) the velocity at t = 3 s.

Answer 1

(a)  the period 

(b) Angular frequency

(c) Amplitude is the maximum displacement from mean position. Hence, A = 2 - 0 = 2 cm

(d) Maximum speed 

(e) The displacement is given by