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in Chemistry by (24.2k points)
Total number of lone pairs on Xe in `XeF_(2), XeO_(3)F_(2), XeF_(4), XeF_(6)` is t,u,v & w respectively. Then
A. `t +u = 3`
B. `v +w = 3`
C. `u = 0`
D. `w = 1`

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