Question

A particle moving on x-axis has potential energy U = 2 - 20x + 5x² J along x-axis. The particle is released at x = -3. The maximum value of x will be

(a) 5 m

(b) 3 m

(c) 7 m

(d) 8 m

Answer 1

Correct option (c) 7 m

Explanation :

F = 0 at x = 2, i.e., x = 2 is the equilibrium position.

As particle is released from x = -3 , so amplitude is 5 m.

Thus, maximum x coordinate is 2 m + 5 m = 7 m.