Let x = [a^2b^2/c] be the physical quantity. If the percentage error in the measurement of physical quantities a, b and c is 2, 3 and 4

Question

Let x = \([\frac{a^2b^2}{c}]\) be the physical quantity. If the percentage error in the measurement of physical quantities a, b and c is 2, 3 and 4 percent respectively then percentage en-or in the measurement of x is

(A) 7% 

(B) 14% 

(C) 21% 

(D) 28%

Answer 1

(B) 14%

Given: x = \(\frac{a^2b^2}{c}\)

Percentage error is given by.

= (2 × 2) + (2 × 3) + 4

= 4 + 6 + 4 = 14

∴ \(\frac{\triangle \text{x}}{\text{x}}\%\) = 14%