**Solution:**

If 7^{n} has to end with the digit 0 for any natural number n,

then it has to be divisible by 10.

ie. its prime factorisation should have the factors of both 2 and 5 [ since 10=2x5 ]

But we know that 7=7x1

By the fundamental theorem of arithmetics, we also know that there exist no other factors for 7.

Thus we conclude that 7^{n} cannot end with the digit 0 for any natural number n.