A solution is `10^(-3)` M each in `Mn^(2+),Fe^(2+),Zn^(2+)` and `Hg^(2+)` is treated with `10^(-16)` M sulphide ion, If `K_(sp)` values of MnS, FeS, ZnS and HgS are `10^(-15),10^(-23),10^(-20)` and `10^(-54)` respectively, which one will precipitate first?
A. FeS
B. MnS
C. HgS
D. ZnS