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An iron tore supports N = 500 turns. Find the magnetic field energy if a current I = 2.0 A produces a magnetic flux across the tore's cross-section equal to Φ = 1.0 mWb.

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To find the magnetic field energy we recall that the flux varies linearly with current Thus, when the flux is Φ for current i, we can write Φ = A i The total energy inclosed in the field, when the current is I, is

The characteristic factor 1/2 appears in this way.

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