Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.5k views
in Physics by (36.9k points)
closed by

A person travelling in a straight line moves with a constant velocity v1 for certain distance x’ and with a constant velocity v2 for next equal distance. The average velocity y is given by the relation

(A) v = \(\sqrt{v_1\,v_2}\)

(B) \(\frac{1}{v}=\frac{1}{v_1}+\frac{1}{v_2}\)

(C) \(\frac{2}{v}=\frac{1}{v_1}+\frac{1}{v_2}\)

(D) \(\frac{v}{2}=\frac{v_1+v_2}{2}\)

1 Answer

+1 vote
by (37.7k points)
selected by
 
Best answer

(C) \(\frac{2}{v}=\frac{1}{v_1}+\frac{1}{v_2}\)

Let, t’ be the time taken to travel distance ‘x’ with constant velocity ‘v1

∴ t1\(\frac{X}{\text{v}_2}\)

Let ‘t2’ be the time taken to travel equal distance ‘x’ with constant velocity ‘v2'

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...