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In the given figure, if ABCD is a trapezium in which AB | | CD | | EF, then prove that AE/ED = BF/FC

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In the given figure, if ABCD is a trapezium in which AB | | CD | | EF, then prove that

AE/ED = BF/FC

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Draw AC intersecting EF at G.

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In fig., EF || DC || AB Then prove that : AE/ED = BF/FC
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