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In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of minor arc of the chord.

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Let ‘O’ be the centre of the circle and AB be the chord of the circle. 

Here, d = 40 cm

∴ r = 40/2 = 20 cm

Since OA = OB = AB, 

∆OAB is an equilateral triangle. 

The angle subtended at the centre by the minor

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