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If `x=2+a+a^2+oo,w h e r e|a|<1a n dy=1+b+b^2+oo,w h e r e|b|<1.` prove that: `1+a b+a^2b^2+oo=(x y)/(x+y-1)`<br>A. `(xy)/(y+x-1)`
B. `(x+y)/(x-y)`
C. `(x^(2)+y^(2))/(x-y)`
D. `(xy)/(y+x+1)`

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