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Given that `a x^2+b x+c=0` has no real roots and `a+b+c<0,` then `c!=0` b. `c<0` c. `c >0` d. `c=0`

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Given that `a x^2+b x+c=0` has no real roots and `a+b+c<0,` then `c!=0` b. `c<0` c. `c >0` d. `c=0`
A. c = 0
B. `c gt 0`
C. `c lt 0`
D. c = 0
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Correct Answer - C
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