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Consider the following equation in a closed container:

N2O4(g)⇄2NO2(g)

At a fixed temprature, the volume of the reaction container is halved.For this change,Which of the following statements, holds true regarding the equilibrium constant (Kp) and degree of dissociation(α)

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Correct option (D)KP does not change, but α changes

Explanation:

For the equilibria: N2O4(g) ⟺ 2NO2(g) KP = KC x (RT)Δn Since temperature is constant so Kc or KP will remain constant. Further since volume ishalved, the pressure will be doubled so α will decrease so as to maintain the constancy of KC or KP.

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