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Solve the following quadratic equation:

x2 + 3ix + 10 = 0

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Given equation is x2 + 3ix + 10 = 0

Comparing with ax2 + bx + c = 0, we get

a = 1, b = 3i, c = 10

Discriminant = b2 – 4ac

= (3i)2 – 4 × 1 × 10

= 9i2 – 40

= -9 – 40 ……[∵ i2 = -1]

= -49 < 0

So, the given equation has complex roots.

These roots are given by

∴ x = 2i or x = -5i

∴ The roots of the given equation are 2i and -5i.

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