Question

The phase difference between two waves, represented by

y₁ = 10^-6 sin [100t +(x/50) + 0.5] m

y₂ = 10^-6 cos [100t+(x/50)] m

where x is expressed in metres and t is expressed in seconds, is approximately.

(a) 1.07 radians 

(b) 2.07 radians

(c) 0.5 radians 

(d) 1.5 radians

Answer 1

Correct option (a) 1.07 radians    

Explanation:

The phase difference = 1.57 - 0.5 = 1.07

[or using sinx = cos(π/2- x). We get the same result.]