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+1 vote
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in Olympiad by (20 points)
Find \( x \) of \( \angle A O C=70^{\circ} \) and \( \angle B A O=50^{\circ} \) where 0 is centre of the circle. (a) \( 35^{\circ} \) (b) \( 30^{\circ} \) (c) \( 25^{\circ} \) (d) \( 15^{\circ} \)

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1 Answer

+1 vote
by (40 points)

Consider △ABO, 

AO=BO

⇒∠BAO=∠ABO=300

Consider △CBO, 

CO=BO,

⇒∠BCO=∠CBO=400

⇒∠ABC=∠ABO+∠CBO=300+400=700

The angle subtended at the centre is twice the angle subtended anywhere on the arc, 

so,

∠AOC=2×∠ABC=140.0

Hope this helps!

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