Question

Consider the following relations for emf of an electrochemical cell

(i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode)

(ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode)

(iii) EMF of cell : (Reductional potential of anode) + (Reduction potential of cathode)

(iv) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)

Which of the above relations are correct?

(a) (iii) and (i)

(b) (i) and (ii)

(c) (iii) and (iv)

(d) (ii) and (iv)

Answer 1

Correct option (d) (ii) and (iv)

Explanation :

EMF of a cell = Reduction potential of cathode - Reduction potential of anode

= Reduction potential of cathode + Oxidation potential of anode

= Oxidation potential of anode - Oxidation potential of cathode.