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0 votes
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in Commercial Mathematics by (36.7k points)
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If (a+1) workers (In number) will do a work in (a+1) days then in how many days will (a+2) members of workers do the work ? 

A) \(\frac{a+2}{(a+1)^2}\)

B) \(\frac{(a+1)^2}{a}\)

C) \(\frac{a+1}{(a+2)}\)

D) \(\frac{(a+1)}{a+2}^2\)

2 Answers

+1 vote
by (57.0k points)
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Best answer

Correct option is (D) \(\frac{(a+1)^2}{a+2}\)

Work done by (a+1) works in (a+1) days = (a+1) (a+1)

\(=(a+1)^2\)

Number of days required to complete the same work by (a+2) members \(=\frac{\text{Total work}}{a+2}\)

\(=\frac{(a+1)^2}{a+2}\)

+2 votes
by (38.9k points)

Correct option is   D) \(\frac{(a+1)}{a+2}^2\)

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