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in Physics by (25.3k points)
The decay constant of radio isotope is `lambda`. If `A_(1) and A_(2)` are its activities at times `t_(1) and t_(2)` respectively, the number of nuclei which have decayed during the time `(t_(1)-t_(2))`
A. `A_(1)-A_(2)`
B. `(A_(1)-A_(2))//lambda`
C. `lambda(A_(1)-A_(2))`
D. `(A_(1)t_(1)-A_(2)t_(2)`

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1 Answer

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by (25.5k points)
Correct Answer - B

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