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in Physics by (25.4k points)
What is the distance of closest approach to the nucleus for an `alpha`-particle of energy 5J MeV which undergoes scattering in the Gieger-Marsden experiment.
A. `3.2xx10^(-16)` m
B. `2xx10^(-14)` m
C. `4.6xx10^(-15)` m
D. `3.2xx10^(-15)` m

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1 Answer

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by (25.1k points)
Correct Answer - B

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