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in Physics by (79.4k points)

From a circular disc of radius R and mass 9M, a small disc of mass M and radius R/3 removed concentrically. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through its centre is

(a) 40/9 MR2

(b) MR2

(c) 4 MR2

(d) 4/9 MR2

1 Answer

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Best answer

Correct option (a) 40/9 MR2

Explanation:

Mass of the disc = 9M Mass of removed portion of disc = M The moment oi inertia of the complete disc about an axis passing through its centre O and perpendicular to its plane is I1= 9/2 MR2

Now, the moment of inertia of the disc with removed portion

There, moment of inertia of the remaing portion of disc about o is

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